0.5x^2+7.5x+8=0

Solution for 0.5x^2+7.5x+8=0 equation:

0.5x^2+7.5x+8=0

a = 0.5; b = 7.5; c = +8;
Δ = b2-4ac
Δ = 7.52-4·0.5·8
Δ = 40.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.5)-\sqrt{40.25}}{2*0.5}=\frac{-7.5-\sqrt{40.25}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.5)+\sqrt{40.25}}{2*0.5}=\frac{-7.5+\sqrt{40.25}}{1}
$